10gm of a Non-Volatile Solute when dissolved in 100 gm of Benzene raises its boiling point by 1c0. What is the Molecular Mass of the solute? (Kb for Benzene=2.53 K Kg/Mole)
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2
Answer:
Answer:
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Explanation:
thanks de do
Answered by
3
Answer:
253
Explanation:
Given :
w = 10gm of Non - volatile solute
in Benzene = 100 gm
Raise in boiling point = 1°C
Kb of benzene = 2.53 K Kg/Mole
To find :
the Molecular Mass of the solute
Formulae :
m = molality =
Solution :
So from the first formula, let us find the molality
1 = 2.53 × m
=> m =1/2.53
So,
From the second formula, let us find the Molecular mass of solute
Hence, The Molecular weight of the solute is 253gm
Hope it helps!
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