Question

10grameach ofhydrogen and nitrogen are allowed react. Mention limiting and excess
reagents find the amount of ammonic formed and the amount of reagent unreacted.
The balanced chemical equation is,
N2(g) +3 H2(g)→ 2N Hg (9)​

Answer 1

Answer:

Explanation:

The molecular weight of H is 2g/mol.

10g of H2

= 10g/(2g/mol)

= 5mol

The molecular weight of N2 is 28g/mol

10g of N2

=10g/(28g/mol)

=0.357mol

According to the equation, 1mol of N2 will react with 3mol of H2 and form mol of NH3

So, 0.357mol N2 will fully react with 0.357*3= 1.071 mol of H2

The rest of the H2 amount will be unreacted that is (5-1.071)=3.929mol

So, here amount of moles of N2 is deciding how much H2 will react and how much NH3 will be formed. so, N2 is the limiting reagent here.

The balanced equation says, 1 mol of N2 will form 2mol of NH3

So, 0.357mol of N2 will form 2*0.357=0.714mol of NH3