Question

10ml 0.2N HCl ,40ml 0.3N HNO3 ,50ml 0.4N H2SO4 are mixed What is the normality of the final solution?​

Answer 1

Explanation:

Ans.0.34Normal

apply the formula N1V1+N2V2+N3V3 / V1+V2+V3

Answer 2

Answer:

0.34 N is the normality of the final solution.

Explanation:

We know that normality is equal to the number of equivalents by volume.

To find the total normality, we use the equation below.

N = (N₁V₁ + N₂V₂ + N₃V₃ + ....) ÷ V (total)

The data given in the question is:

1. Volume of HCl = 10 ml
2. Volume of HNO₃ = 40 ml
3. Volume of H₂SO₄ = 50 ml
4. Normality of HCl = 0.2 N
5. Normality of HNO₃ = 0.3 N
6. Normality of H₂SO₄ = 0.4 N

We substitute these values in the equation to calculate the total normality.

N = $\frac{(0.2*10) + (0.3*40) + (0.4*50)}{10 + 40 +50}$

= 0.34 N

Conclusion:

The total normality of the solution is 0.34 N.