10ml hydrogen gas reacts with 5ml of oxygen gas?
hiiii
Answers
Answered by
0
Answer:
Law of constant composition
Explanation:
First case:
Weight of 10 mL of H
2
at STP =
22400
10×2
=0.0008 g
Weight of 5 mL of O
2
at STP =
22400
5×32
=0.0007 g
Second case:
Weight of 200 mL of H
2
at STP =
22400
200×2
=0.0178 g
Weight of oxygen taken away from cupric oxide by 200 mL or 0.0178 g of H
2
at STP =0.144 g.
Weight of O
2
that combines with 0.0008 g of H
2
in first case =
0.0178
0.144×0.0008
=0.0065≈0.007 g.
Thus, the weights of O
2
that combine with same weight of H
2
is the same in two cases. Hence, the law of constant composition is proved.
Hence, it illustrates the law of constant composition.
Answered by
0
Answer:
law of constant proportion
Attachments:
Similar questions