Question

10mL of 0.2N HCl and 30mL of 0.1N HCl to gether exaclty neutralises 40mL of solution of NaOH, which is also exactly neutralised by a solution in water of 0.61g of an organic acid. What is the equivalent weight of the organic acid?

Answer 1

Answer:

122

Explanation:

10 ml of 0.2 N HCl + 30 ml of 0.1 N HCl = 40 ml of NaOH (0.61 g organic acid)

meq. of HCl= meq of NaOH = meq of organic acid

$\boxed{10 * 0.2 + 30*0.1 = \frac{0.61}{E} *1000}$

E is the equivalent weight of the organic acid.

$5=\frac{0.61*1000}{E}$

$E=\frac{160}{5} \\\\\boxed{=122}$