10mL of 1N HCl, 20mL of N/2
H2SO4 & 30mL
of N/3
HNO3 are mixed together & volume
made to one litre. The normality of H+
in the
resulting solution is
1) 3N/100
2) N/10
3) N/20
4) N/40
Answers
Answered by
0
Answer:
please send me the DJ Alok
Answered by
0
Answer:
We know
Meq= N × V
where Meq is the equivalent molarity
N is normality of the solution
V is volume of solution
Applying the formula to each of the solution separately
1) HCl
Meq= 1× 5 = 5M
2) H2SO4
Meq=
2
1
×20=10 M
3) HNO3
Meq=
3
1
×30=10 M
For total solution
Meq = M1 + M2 + M3
Meq = 5+10+10 = 25 M
and volume = 1000 mL
Thus applying the same formula
Meq= N × V
25 = N× 1000
N= $$\dfrac{25}{1000} N
=
40
N
Thus normality of the solution would be
40
N
.
Hence, the correct option is D
Similar questions