Question

10ml of 4M H2so4 titrated against NaOH solution prepared by 40g of NaOH/litre.find volume of NaOH

Answer 1

Answer : The volume of NaOH is, 40 ml

Explanation :

First we have to calculate the molarity of NaOH.

$\text{Molarity of NaOH}=\frac{\text{Mass of NaOH}}{\text{Molar mass of NaOH}\times \text{volume of solution}}=\frac{40g}{40g/mole\times 1L}=1mole/L=1M$

Now we have to calculate the volume of NaOH.

To calculate the concentration of acid, we use the equation given by neutralization reaction :

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=4M\\V_1=10mL\\n_2=1\\M_2=1M\\V_2=?$

Now put all the given values in above equation, we get :

$2\times 4M\times 10ml=1\times 1M\times V_2\\\\V_2=40ml$

Hence, the volume of NaOH is, 40 ml