Question

10ml of 4M H2so4 titrated against NaOH solution prepared by 40g of NaOH/litre.find volume of NaOH

Answer 1

Answer:

The volume of NaOH is 80 mL.

Explanation:

To calculate the concentration of acid, we use the equation given y neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

Molarity of NaOH =$M_2$

$M_2=\frac{40 g}{40 g/mol\times 1L}=1 M$

We are given:

$n_1=2\\M_1=4 M\\V_1=10 mL\\n_2=1\\M_2=1 M\\V_2=?$

Putting values in above equation, we get:

$2\times 4 M\times 10 mL=1\times 1 M\times V_2\\\\V_2=80 mL$

The volume of NaOH is 80 mL.