Question

10ml of M NaoH solution is neutrilized by the following volume of 1 M H2So4

Answer 1

We know that the balance reaction of NaOH and H2SO4 is as follows:

2 NaOH + H2SO4 ---- > Na2SO4   + H2O

Moles of NaOH = molarity * volume in L

= 1 mole / L* 10 ml  *1L/1000 ml

= 0.01 mole NaOH

Now calculate the moles of H2SO4

0.01mole NaOH * 1 mole H2SO4 /2 mole NaOH

=0.005 Mole H2SO4

And molarity = number of moles / volume in L

Volume in L= number of moles / molarity  

= 0.005 Mole H2SO4 /1 M

= 0.005 L H2SO4

= 5 ml H2SO4