10ml of solution of NaOH is round to be completely neutralised by 8ml of a given solution of HCL. If we take 20ml solution of NaOH, the amount of HCL (the same as before) required to neutralise it, will be?
Choose the correct option:-
a)4ml b)8ml c)12ml d)16ml
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option d) 16
because the ratio of neutralisation of the chemical was 10:8 so the double of it will be 20: 16
because the ratio of neutralisation of the chemical was 10:8 so the double of it will be 20: 16
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