Question

10ohm electric heater operates on 110 volt. Then the rate at which it delops heat in watt
will be

Answer 1

Explanation:

I hope you have understand by above pic

Answer 2

Given:-

• A electric heater has a power of 10 Ω.
• The electrical heater rate is 110 volt.

To Find:-

• The rate at which he develops in watt.

Formula Used:-

We know that Power is equal to ,

$\large{\underline{\boxed{\red{\tt{ \leadsto Power=\dfrac{(Voltage)^2}{Resistance}}}}}}$

where

• V is Voltage .
• R is the resistance .

Answer:-

Rate at which heat develops will be equal to the power of the electrical heater.

Voltage at which the electrical heater operates = 110V .

Resistance of the the heater = 10Ω.

Putting the values in the above formula stated we have:-

⇒ Power = Voltage ²/ Resistance.

⇒ Power = 110 V ² / 10Ω.

⇒ Power = 110 × 110 V² / 10Ω .

⇒ Power = 1210 V²/ Ω = 1210 Watt.

Hence the power how the electrical heater is 1 to 10 watt.

More to Know:

Apart from the above formula stated we also have other formula for finding the power which are:

• Power = Voltage ²/Resistance.
• Power = Voltage × Current.
• Power = Current ² × Resistance.

Let voltage be denoted by V resistance by R and current by I ; we get :-

• V²/R = I²R = VI = Power.

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Also have a look at the Ohm's Law :

$\large{\underline{\underline{\red{\tt{\underbrace{\overbrace{\dag Ohm's \:Law:- }}}}}}}$

Ohm's law states that the if the physical conditions are remain unchanged , the thethe potential difference across the two ends of a conductor is directly proportional to the electrical current flowing through it.

Mathematically ,

$\sf{\implies V \propto I }$

$\bf{\implies V = IR }$

where R is the constant of proportionality and is called the resistance of the conductor it is a property of a conductor to resist the flow of charge through it.