Question

10P. A car moves with a speed of
30km/hr for 3 hours and then moves
with a speed of 40km/hr for 2 hours.
What is the magnitude of average
velocity of the car?​

Answer 1

$\mathcal{\green{\underline{\blue{GIVEN:}}}}$

• A car moves with a speed of 30Kmhr⁻¹ for 3 hours.
• Then it moves 40kmhr⁻¹ for 2 hours.

$\mathcal{\green{\underline{\blue{TO \:\: FIND:}}}}$

• The magnitude of the average velocity of the car.

$\mathcal{\green{\underline{\blue{SOLUTION:}}}}$

$\bf Displacement = Speed \times Time$

$\bf D_1=30\times 3=90$

$\bf D_2=40\times2=80$

We know that average velocity :

$\bf {\pink{V_{Average}=\frac{Total \:\: distance }{Total \:\: time} }}$

$\bf V_{av}=\frac{90+80}{3+2}$

$\bf V_{av} = \frac{170}{5}$

$\bf V_{av} = 34 Kmhr^{-1}$

$\huge\star\:\:{\orange{\underline{\pink{\mathbf{HOPE \:\: THIS \:\: HELPS \:\: :D}}}}}$

Answer 2

Answer:

34km/hr

Explanation:

let car A travels with speed of 30km/hr in 3hrs

let car B travels with speed of 40km/hr in 2hrs

Average velocity= total displacement/total time

total time = 2+3= 5hrs

total displacement= speed*time

                              = (30*3)+(40*2)=170

therefore, 170/5= 34km/hr