10pq=p²-q² 13 q(p²+q2)
Answers
Answered by
0
10pq = p^2-q^2+13q(p^2+q^2)
10pq = p^2-q^2(1-13q)
10pq/1-13q = p^2-q^2
Similar questions
English,
3 months ago
English,
3 months ago
Math,
3 months ago
Math,
7 months ago
Physics,
7 months ago
Computer Science,
1 year ago
Computer Science,
1 year ago