Question

10std
${x }^{2} + 4x - 5 = 0 .x = 1. - 1$
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Answer 1

Answer:

x2 + 4x – 5 = 0 , x = 1 , -1 For x = 1 ( 1 ) 2 + 4 ( 1 ) – 5 = 0 + 1 + 4 – 5 = 0 => 5 – 5 = 0 So , x = 1 is a solution of the given equation. For x = -1 ( -1 ) 2 +4 ( -1 ) – 5 = 0 + 1-4-5 = 0 + -3 – 5 = 0 → -840 So , x = -1 is not a solution of the given equation. Thus , only x = 1 is root of the given equation .