Question

10t^2+ t - 30 find the value of t pls do fast plsssss.....

Answer 1

We have,

10t²+t-30=0
10t²+t=30
10t²=30-t
t²=(30-t)/10
t²=30/10-t/10
t²=3-(t/10)
t=√3-√t/√10
t=√3-√t/√10*√10/√10
t=√3-√10t/10


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Answer 2

Answer:

Step-by-step explanation:

Given Expression,

f(t)= 10 t²+t-30

Use quadratic equation,

t= -b±√b²-4 ac/2 a

D = b²-4 a c

Where

b= coefficient of t = 1

a= coefficient of t² = 10

c= constant term = -30

D = (1)²- 4*10*(-30)

= 1+1200

= 1201

√1201 = 34.65

t = -b±√b²-4 ac/2 a

t = -1±34.65/2*10

t = -1+34.65/20

t= 33.65/20

t =  3.365/2

t = 1.6825

t = -1-34.65/20

= -35.65/20

= -3.565/2

= - 1.7825

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