Question

10th board question of Algebra paper ...
plzz solve
giving 30 points​

Answer 1

Answer:

x = $\frac{16}{17}$ , y = $\frac{1}{17}$

Step-by-step explanation:

$\sqrt{\frac{x}{y} } = 4$

Squaring both sides,

or, $\frac{x}{y} = 4^{2}$

or, $\frac{x}{y} = 16$

or, x = 16y .... (1)

And,

$\frac{1}{x} + \frac{1}{y} = \frac{1}{xy}$

or, $\frac{y + x}{xy} = \frac{1}{xy}$

or, x + y =1 ... (2)

Substituting value of x from (1) in (2), we get

16y + y = 1

or, 17y = 1

or, y = $\frac{1}{17}$

Putting the value of y in (1)

x = $\frac{16}{17}$

Answer 2

Step-by-step explanation:

answer is in the attachment

hope it is helpful for you