Question

10th class solution only please

Answer 1

Since the diagonals of a parallelogram, bisect each other, therefore co-ordinates of mid-point of AC = co-ordinates of mid-point of BD..

Let the D vertex be (x,y)
BD and AC are diagonals...

the mid points are equal..

Mid point formula=(x1+x2/2),(y1+y2/2)
AC mid points=(3-6/2),(-4+2/2)
=(-3/2,-1)

BD mid point= (x-1/2,y-3/2)

x-1/2=-3/2
x-1=-3
x=-3+1
x=-2..

y-3/2=-1
y-3=2
y=3+2=5..


Hence the coordinates of D are (-2,5)..

Hope this helps!!
cheers! (: