10th maths the ratio of 6th And 8th terms that are in A. P. is 7;9.find the ratio of 9th term to 13th term.
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ratio of 6th and 8th term =a+5d/a+7d= 7/9
7( a+7d)= 9(a+5d)
7a+49d = 9a +45d
49d-45d= 9a-7a
4d = 2a
a= 2d
ratio of 9th and 13th term
= a+8d / a+12d = 2d +8d / 2d+12d = 10d /14d = 10/14 = 5/7
ratio of 9th and 13th term = 5:7
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