10th of an arithmetic sequence is 30 and common difference is 4 find the 1st term
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given ,
a10 => 30 = a + 9d
=> 30 = a + 9(4)
=>30 - 36 = a
=> -6 = a ; which is the required first term
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Answer:
use n term = a + ( n-1) d
then we get by putting n=10
we get a= -6
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