Question

10th std maths Ex 4.2 Qn No 1


(iii) (x-2)(x+1)=(x - 1)(x + 3)
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Answer 1

Step-by-step explanation:

The given equation is :-

$(x - 2)(x + 1) = ( x - 1)(x + 3) \\ {x}^{2} + x - 2x - 2 = {x}^{2} + 3x - x - 3 \\ {x}^{2} - x - 2 = {x}^{2} + 2x - 3 \\ 3x - 1 = 0$

it is not ax^2 + bx + c = 0

therefore , given equation is not a quadratic equation