10th std maths first term is 30 the sum of the first six terms is300
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Answer:
First term of AP:
30
Sum of first 6 terms of AP:
300
300 = n/2[2a+(n-1)d] {by formula}
a = 30
n = 6
⇒ 300 = 6/2[2{30}+(6-1)d]
300 = 3[60+5d]
300/3 = 60+5d
100 = 60+5
100-60 = 5d
40 = 5d
40/5 = d
8 = d
Now, we find the first 6 terms of AP:
a = 30
d = 8
1st term = a
= 30
2nd term = 30+8
= 38
3rd term = 38+8
= 46
4th term = 46+8
= 54
5th term = 54+8
= 62
6th term = 62+8
= 70
VERIFY:
30+38+46+54+62+70 = 300
100+100+100 = 300
300 = 300
LHS = RHS
Hence, verified
Hope it helps
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