Question

10th term of 4 + 6 + 8 + ......
... is​

Answer 1

$\huge\mathfrak{\fcolorbox{red}{gray}{\green{A}\pink{N}\orange{S}\purple{W}\red{E}\blue{R}{!}}}$

a = 4

a = 4d = ${a}_{2}-{a}_{1}$ = 6 - 4 = 2

a = 4d = ${a}_{2}-{a}_{1}$ = 6 - 4 = 2 n = 10

A.T.Q.

${a}_{n}=a+(n-1)d$

$\mapsto{a}_{10}=4+(10-1)2$

$\mapsto{a}_{10}=4+(9)2$

$\mapsto{a}_{10}=4+18$

$\huge{\boxed{\red{{a}_{10}=22}}}$

Answer 2

a = 4

a = 4d = aaj = 6 - 4 = 2

a = 4d = a2 - a = 6 - 4 = 2 n = 10

A.T.Q.

an = a + (n 1)d

H a10 = 4+ (10 – 1)2

a10 = 4 + (9)2

H a10 = 4 + 18 =

a10 = 22