10th term of an ap is equal to 7 minus 3 then second term is
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Step-by-step explanation:
10th term is equal to. a+(n-1)d
a+(n-1)d= 3n + 5
On opening bracket on l.h.s.
dn + (a-d)= 3n + 5.
On comparing both the sides.
dn= 3n therefore d=3.
Also a-d = 5
a-3 =5
a= 8
Seventh term = 8+ (7–1)×3
Seventh term = 8+18
The answer is 26.
hope it will help you
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