10th term of AP is 10 more than 5th term and their sum is 32. find series
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Answer:
here mate
Step-by-step explanation:
T10=a+9d
T5 =a+4d
T10=T5+10
a+9d= a+4d+10
5d=10
d=2
Sum of T10+T5 =a+4d+a+9d =32
2a+13d =32
2a+26=32
2a=6
a=3
d=2
AP series
3 5 7 9 11 ---
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