Question

10th term of the AP 1/2 3/2 5/2 .....

Answer 1

Answer:

given,

a=1/2

d=3/2-1/2=1

a10=?

solution,

an=a+(n-1)d

a10=1/2+(10+1)1

=1/2+(9)1

=1/2+9

=1+18/2

a10=19/2

10th term of given AP is 19/2.

Answer 2

Answer:

$\large\boxed{a_{10}=\frac{19}{2} }$

Step-by-step explanation:

❂ Given:-

A.P. :- $\frac{1}{2},\frac{3}{2},\frac{5}{2},...$ , where a=$\frac{1}{2}$, d=1

❂ To Find:-

   a₁₀(10th term of this A.P.)

❂ Formula Applied:-

    aₙ=a+(n-1)d

❂Solution:-

   aₙ=a+(n-1)d, where a=$\frac{1}{2}$, d=1, n=10.

⇒ a₁₀=$\frac{1}{2}$+[(10-1)×(1)]

$\implies a_{10}=\frac{1}{2}+9$

$\implies a_{10}=\frac{1+18}{2}$

$\implies\boxed {a_{10}=\frac{19}{2}}$