Question

10x^2+11x+3=4x^2+9x+7

Solve for values that make the equation true

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

${10x}^{2} + 11x + 3 = {4x}^{2} + 9x + 7 \\ {10x}^{2} + 11x + 3 - {4x}^{2} - 9x - 7 = 0 \\ </p><p> {6x}^{2} + 2x - 4 = 0 \\ {6x}^{2} + 6x - 4x - 4 = 0 \\ 6x(x + 1) - 4(x + 1) = 0 \\ (6x - 4)( x+ 1) = 0 \\ 1) = > 6x - 4 = 0 = x = \frac{4}{6} = \frac{2}{3} \\2) (x + 1) = 0 = x = - 1$