Question

[(10x^3y^2-15x^2y^2+5xy^2)+(2x^2y+4)-(6x^2y-xy^2-15x^3y^2)]

Answer 1

Answer:

Solve the following pairs of equations by reducing them to a pair of linear equations:

(i) 2x1+3y1=2;3x1+2y1=613

(ii) x2+y3=2;x4−y9=−1

(iii) x4+3y=14;x3−4y=23

(iv) x−15+y−21=2;x−16−y−23=1

(v) xy7x−2y=

Step-by-step explanation:

(i)

2x1+3y1=2

3x1+2y1=613

Lets assume x1=p and y1=q, both equations will become

2p+3q=2

⇒3p+2q=12    ... (A)

3p+2q=613

⇒2p+3q=13   ...(B)

Multiply (A) by 3 and (B) by 2, we get

9p+6q=36

4p+6q=26

Subtracting these both, we get

5p=10

⇒p=2

⇒x=p1=21

∴q=626−8=