Question

10x²+10x+1=0 find value of a+b=? axb=?​

Answer 1

Answer:

a=10. b=10. c=1

alpha + beta= -b/a=-10/10=-1

Explanation:

Q. 10x²+10x+1=0

Ans- we know that,

In the quadratic equation,

a=10,b=10,c=1

since, alpha +bita=-b/a

then,from the quadratic equation valueod a,b,c we have,

alpha+bita=-(10)/10=-10/10=-1(cancelled 10)

Then the value of alpha+bita =-1.

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Answer 2

Answer:

(i) -1

(ii) $\frac{1}{10}$

Explanation:

ax²+bx+c=10x²+10x+1

Substituting the values:-

a=10, b=10, c=1

(i) α+β=(-b)/a=(-10)/10=(-1)

(ii) α×β=c/a=1/10= 0.1