Question

10x²-27x+5=0
plz solve it plz​

Answer 1

Answer:

to solve I m using determinant method.

D=b^2-4ac

=(-27)^2-4•10•5

=729-200

=529

and x=(27+√529)/20

and

x=(27-√529)/20

hope it helps ...

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Answer 2

Answer:

$x = 2\frac{1}{2} \\ x = \frac{1}{5}$

Step-by-step explanation:

$10 x^{2} - 27x + 5 = 0 \\ 10x^{2} - (25 + 2)x + 5 = 0\\ {10x}^{2} - 25x - 2x + 5 = 0\\ 5x(2x - 5) - 1(2x - 5) = 0 \\ (2x - 5)(5x - 1) = 0 \\ \\ 2x - 5 = 0 \\ 2x = 5 \\ x = \frac{5}{2 } \\ x = 2\frac{1}{2} \\ \\ 5x - 1 = 0 \\ 5x = 1 \\ x = \frac{1}{5}$

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