Question

-10x2+31x-24=(t-2x)(5x-s) Then ts is

Answer 1

GIVEN :

The equation is $-10x^2+31x-24=(t-2x)(5x-s)$

TO FIND :

The value of ts from the given equation.

SOLUTION :

Given equation is $-10x^2+31x-24=(t-2x)(5x-s)$

Now solving the given equation to get the value of ts:

$-10x^2+31x-24=(t-2x)(5x-s)$

By using the Distributive property:

(a-b)(c-d)=(a-b)c-(a-b)(d)

$-10x^2+31x-24=(t-2x)(5x)-(t-2x)(s)$

By using the Distributive property:

(a-b)x=ax-bx

$-10x^2+31x-24=t(5x)-2x(5x)+t(-s)-2x(-s)$

$-10x^2+31x-24=5tx-10x^2-ts+2xs$

$-10x^2+31x-24=-10x^2+(5t+2s)x-ts$

Now equating the constant term in the above equation,

-24=-ts

24=ts

Rewritting the above equation we have that

ts=24

∴ ts=24 where ts is the constant term of the given equation.

∴ the value of ts constant term in the given equation is 24.