Question

10y-0.2(7-y)=19 solve the equation.​

Answer 1

Step-by-step explanation:

$= 10y - 0.2y(7 - y) = 19 \\ = 10y - 1.4y + 0.2 {y}^{2} = 19 \\ = 0.2 {y}^{2} + 8.6y - 19 = 0 \\ = \frac{2 {y}^{2} }{10} + \frac{86y}{10} - 19 = 0 \\ \\ = 2 {y}^{2} + 86y - 190 = 0 \\ =$

Answer 2

$\Large\frak{\underline{\underline{Answer:}}}$

$= 10y - 0.2y(7 - y) = 19 \\ = 10y - 1.4y + 0.2 {y}^{2} = 19 \\ = 0.2 {y}^{2} + 8.6y - 19 = 0 \\ = \frac{2 {y}^{2} }{10} + \frac{86y}{10} - 19 = 0 \\ \\ = 2 {y}^{2} + 86y - 190 = 0 \\ =$