10y -(2y-1)=41
Without adding find the sum : a) 1+2+3+4+5+7+9+11 b) 1+2+3+.............+21
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Step-by-step explanation:
3.33
a) 37
b) 231
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Answered by
0
Step-by-step explanation:
10y-(2y-1)= 41
solving the bracket by multiplying the subtract sign with it
10y-2y+1 = 41
8y= 41-1= 40
y= 40/8
y= 5
2a) 42
b) can be find out by using A. P. sum formula
= Sn= n/2(2a+ (n-1) d
here a= 1 d= 1 n= 21
so Sn = 21/2(2×1+(21-1) 1
= 21/2(2+20)
21/2× 22
now 2 will cancel 22 with 11
= 21×11
= 231
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