Question

10years ago a mans age was 6 times the age of his son . 12 years later , the age of his son . 12 years later , age of the son will be 27 years . what is the present age of the father

Answer 1

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Hello Shanaya...

let the child's age be = x

10 years ago man's age was 6 times of son

so 10 years before father's age=6x

now 6(x-10 )

12byears later sons age =27

so x+12=27

equations are

father's current age=6(x-10)

sons age after 12 years x+12=27

x can be

x=27-12

x=15

sons current age=15

father's age =6(x-10)

6 X (15-10)

6 X 5

30

current age of father = 30yrs

percent = 30%

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