Math, asked by maina1640, 10 months ago

10years ago father was 12 times as old as his son and 10years later he will be twice as old as his son.The ratio of father and sons present age is​

Answers

Answered by rupamtiwari917
1

Let,

the Present age of the Son = x years

the Present age of the Father = y years

Acocording to the Conditions,

y - 10  = 12 ( x - 10) → 12x - y = 110...............1)

y + 10 = 2 ( x + 10 ) → 2x - y = -10  ................2)

Subtracting 2) from 1), we get

x = 12

Substituting the value of x = 12 in equation 2), we get

y = 34

Therefore the Present age of Son and Father is 12 years and 34 years respectively.

Answered by krrew
0

Answer:

The Present age of Son and Father is 12 years and 34 years respectively.

Step-by-step explanation:

Let,

the Present age of the Son = x years

the Present age of the Father = y years

Acocording to the Conditions,

y - 10  = 12 ( x - 10) → 12x - y = 110...............1)

y + 10 = 2 ( x + 10 ) → 2x - y = -10  ................2)

Subtracting 2) from 1), we get

x = 12

Substituting the value of x = 12 in equation 2), we get

y = 34

Therefore the Present age of Son and Father is 12 years and 34 years respectively.

Hope this helps

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