Question

10years ago father was 12 times as old as his son and 10years later he will be twice as old as his son.The ratio of father and sons present age is
(a) 6:1 (b) 17:6 (c) 7:6 (d) 16:7​

Answer 1

Answer:

7:6 the correct answer

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Answer 2

Step-by-step explanation:

let fathers age=x

let sons age=y

fathers age before 10 yrs= x-10

sons age before 10 yrs=y-10

according to question,

x-10=12(y-10)

x=12y-120+10

x=12y-110-----(1)

age of father after 10yrs=x+10

age of son after 10 yrs=y+10

according to question,

x+10=2(y+10)

x+10=2y +20

substituting (1)

12y-110+10=2y+20

12y-100=2y+20

12y-2y=20+100

10y=120

y=120/10

y=12

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therefore,x= 12y-110

x=12(12)-110

x=144-110

x= 34