Question

10years hence, the age of x will 2 times that of age of y, 10years ago, the age of x was six times that of age y. what is the present ages​

Answer 1

Answer:

Let age of X be a

And age of Y be b

According to question

10 years from now

a + 10 = 2(b + 10)

= a + 10  =  2b + 20

Therefore a - 2b = 10   -----1

And ten years ago

a  - 10 = 6(y - 10)

= a - 10 = 6b -60

Therefore 6b - a = 50   ------2

Adding 1 and 2

6b - a = 50

-2b + a = 10

= 4b = 60

Therefore b = 15

Substituting in 1 we get

a = 40

Therefore X is 40 years old

And Y is 15 years old

hope this helped

Read more on Brainly.in - https://brainly.in/question/12182623#readmore