Question

10years hence the age of X will be two times that of age of Y, 10 years ago, the age of X was 6 times that of age of Y.what are their present age
plz answer this question ​

Answer 1

Answer:

Age of X = 40 years

Age of Y = 15 years

Step-by-step explanation:

Let present ages of X be x years

                                 Y be y years.

Case 1

10 Years hence or 10 years after

Age of X = (x+10) years

Age of Y = (y+10) years

A.T.Q

(x+10) = 2(y+10)

x-2y = 10                    - eq.1

Case 2

10 Years ago or before

Age of X = (x-10) years

Age of Y = (y-10) years

A.T.Q

(x-10) = 6(y-10)

x-6y = -50                - eq.2

Solve it with elimination method