10z²-7z-12 factories
Answers
Answer:
(5z+4)(2z-3)
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
((0 - (2•5z2)) + 7z) - 12
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
-10z2 + 7z - 12 = -1 • (10z2 - 7z + 12)
Trying to factor by splitting the middle term
3.2 Factoring 10z2 - 7z + 12
The first term is, 10z2 its coefficient is 10 .
The middle term is, -7z its coefficient is -7 .
The last term, "the constant", is +12
Step-1 : Multiply the coefficient of the first term by the constant 10 • 12 = 120
Step-2 : Find two factors of 120 whose sum equals the coefficient of the middle term, which is -7 .
-120 + -1 = -121
-60 + -2 = -62
-40 + -3 = -43
-30 + -4 = -34
-24 + -5 = -29
-20 + -6 = -26
STEP 1: Equation at the end of step
((0 (2.5z²)) + 7z) - 12
STEP 2: Pulling out like terms
3.1
Pull out like factors:
- 10z² +7z - 12 = -1 (10z²-7z+12)
Trying to factor by splitting the middle term
3.2
Factoring 10z²-7z+12
The first term is, 10z2 its coefficient is 10.
The middle term is, -7z its coefficient is -7.
The last term, "the constant", is +12
Step-1 Multiply the coefficient of the first term by the constant 10 12 = 120
Step-2: Find two factors of 120 whose sum equals the coefficient of the middle term, which is -7.
-120 + -1 = -121
-60 + -2 = -62
- 40+-3 = -43
-30 + -4 = -34
-24 + -5 = -29
-20 + -6 = -26
For tidiness, printing of 26 lines which failed to find two such factors, was suppressed
Observation: No two such factors can be found !!