Math, asked by Ana2007, 11 days ago

10z²-7z-12 factories​

Answers

Answered by 11096
0

Answer:

(5z+4)(2z-3)

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 ((0 -  (2•5z2)) +  7z) -  12

STEP

2

:

STEP

3

:

Pulling out like terms

3.1     Pull out like factors :

  -10z2 + 7z - 12  =   -1 • (10z2 - 7z + 12)  

Trying to factor by splitting the middle term

3.2     Factoring  10z2 - 7z + 12  

The first term is,  10z2  its coefficient is  10 .

The middle term is,  -7z  its coefficient is  -7 .

The last term, "the constant", is  +12  

Step-1 : Multiply the coefficient of the first term by the constant   10 • 12 = 120  

Step-2 : Find two factors of  120  whose sum equals the coefficient of the middle term, which is   -7 .

     -120    +    -1    =    -121  

     -60    +    -2    =    -62  

     -40    +    -3    =    -43  

     -30    +    -4    =    -34  

     -24    +    -5    =    -29  

     -20    +    -6    =    -26  

Answered by suhaniraikwar
0

STEP 1: Equation at the end of step

((0 (2.5z²)) + 7z) - 12

STEP 2: Pulling out like terms

3.1

Pull out like factors:

- 10z² +7z - 12 = -1 (10z²-7z+12)

Trying to factor by splitting the middle term

3.2

Factoring 10z²-7z+12

The first term is, 10z2 its coefficient is 10.

The middle term is, -7z its coefficient is -7.

The last term, "the constant", is +12

Step-1 Multiply the coefficient of the first term by the constant 10 12 = 120

Step-2: Find two factors of 120 whose sum equals the coefficient of the middle term, which is -7.

-120 + -1 = -121

-60 + -2 = -62

- 40+-3 = -43

-30 + -4 = -34

-24 + -5 = -29

-20 + -6 = -26

For tidiness, printing of 26 lines which failed to find two such factors, was suppressed

Observation: No two such factors can be found !!

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