Question

11.00 AM to 01.00 PM
Question
Calculate the quantity of Potassium Permanganate
required to prepare 1 Pint of a 1 in 20 solution
Option 1:
20.0 gm
Option 2:
30.0 gm
Option 3
25.0 gm
Option 4
15.0 gm​

Answer 1

Answer:

One liter 1N solution of KMnO

4

corresponds to 1 g equivalent. In acid medium for oxidation, the equivalent weight of KMnO

4

is one fifth of its molecular mass. It is

5

158

=31.6.

Hence, 1 g equivalent of KMnO

4

corresponds to 31.6 g.

Hence, in order to prepare one liter 1N solution of KMnO

4

, 31.6 grams of KMnO

4

are required, if the solution to be used in acid medium for oxidation.