Question

11.00 x = 8a 12 1218) In the figure CD is a the bisede of LECB, LB = LACE LACE. Prove that LADC = LACD 2x A 1.00 두 E 2.00 32 3.00 B 4.00​

Answer 1

Answer:

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step by step explanation

Answer 2

Answer:

not understand the questions

Produce DE to intersect BC at P (say).

EF || BC and DP is the transversal ,

∴ ∠ DEF = ∠ DPC .(i) [Corres. ∠ s]

Now , AB || DP and BC is the transversal,

∴ ∠ DPC = ∠ ABC (ii) [Corres. ∠ s]

From (i) and (ii) , we get

∠ ABC = ∠ DEF

Hence , proved.

solution