Question

₹11,000 is invested at 6% interest p.a. Find the interest and the amount at the end of two years.​

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt ₹11,000\: is \:invested\: at\: 6\%\: interest\: p.a. \:\\\tt Find\: the\: interest\: and\: the\: amount\: at\: the\\\tt end\: of\: two \:years.$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf Principal\:amount(P) = ₹11000$
• $\sf \bf Rate\:of\:intrest(r) =6\%$
• $\sf \bf Time(t) =2\:years$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Simple \:Intrest$
• $\sf \bf Total\:amont$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\boxed {\boxed {\color{blue} {S.I=\dfrac{P \times r \times t}{100}}}}}$

$\sf \bf S.I=Simple \:intrest$

$\sf \bf P=principal$

$\sf \bf r=rate\:of\:intrest$

$\sf \bf t=time$

$\tt {\underbrace {Substitute\:the\:values}}$

$\sf \bf \implies S.I=\dfrac{11000 \times 6 \times 2}{100}$

$\sf \bf \implies S.I=\dfrac{132000}{100}$

$\sf \bf \implies S.I=\dfrac{1320\cancel {00}}{1\cancel {00}}$

$\implies {\boxed {\color{green} {\sf \bf Simple \:Intrest(S.I) =1320}}}$

------------------------------------------------------------

${\boxed {\boxed {\color{orange} {\sf \bf Total\:amount=(principal) +(Simple \:intrest)}}}}$

$\sf \bf \implies Total\:amount=11000+1320$

$\implies {\boxed{\color{red} {Total\:amount=₹12320}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

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$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\tt {\overbrace {\underbrace {\color{purple}{Simple\:intrest}}}}$

$\tt Simple\: interest\: is\: interest\: calculated\: on\\\tt the \:principal\: portion\: of \:a\: loan \:or\: the \:original\\\tt contribution\: to\: a \:savings\: account\:. Simple\: interest\\\tt does\: not\: compound\:, meaning\: that \:an\: account\:\\\tt holder \:will \:only\: gain\: interest\: on\: the\\\tt principal\:, and\: a\: borrower\: will\: never\: have\: to\\\tt pay\: interest\: on\: interest\: already\: accrued.$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$