Question

11.1.)
If 'S' is the sum of a finite A.P. whose first term is 'a'
and last term is 'l'show that its common difference is
equal to L2-a2/2s-a-L​

Answer 1

Answer:

Proof

Step-by-step explanation:

S = n(a+L)/2

Therefore n = 2S/(a+L)

Now, d=(L-a)/(n-1)

=(L-a)/{(2S/(a+L) - 1 }

=(L-a)/{(2s -1(a+L)}/(a + L)

={(L-a)(L+a)}/2s - a - L

L^2 - a^2/2s - a - L