Question

√11√11√11.......…
Infinity

Answer 1

Answer:

11

Step-by-step explanation:

Let √(11√(11√(...))) be x

x=√(11√(11...))

=> x²=11*√(11√(11...))

=> x²/11=√(11√(11...))

=> x²/11=x

=> x²=11x

=> x*x=11*x

=> x=11

Actually, this is just approximate, as the value of the given expression √(11√(11√(11...))) is also approximate/indefinite.