Question

11,12,28,109,365,....,?

Answer 1

i)11
ii)11+3^0=11+1=12
iii)12+4^2=12+16=28
iv)28+3^4=28+81=109
v)109+4^4=109+256=365
vi)365+3^6=365+729=1094
required number=1094

Answer 2

11+1^4=11+1=12
12+2^4=12+16=28
28+3^4=28+81=109
109+4^4=109+256=365
365+5^4=365+625=990
HOPE IT HELP...