Question

11.13 Rationalise the given statements and give chemical reactions :
Lead(II) chloride reacts with Cl, to give PbCl.
Lead(IV) chloride is highly unstable towards heat.
Lead is known not to form an iodide, PbI

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Answer 1

Answer:

(a) Due to inert pair effect, Pb(II) is more stable than Pb(IV). Hence, there is no reaction between PbCl2 and Cl2.

(b) Due to inert pair effect, Pb(II) is more stable than Pb(IV). Hence, PbCl4 is thermally unstable and on heating decomposes to form PbCl2

PbCl 4= PbCl +CI2

(c) PbI 4 does not exist due to strong oxidizing power of Pb(IV) and strong reducing power of I -

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