Question

11.1g of cacl2 is in 100ml solution. chloride ion concentration is?

Answer 1

Concentration in molarity , M = moles of CaCl2 /volume in L
And moles of CaCl2 = mass/molar mass mass = 11.1g molar mass = 111g/mol (40 + 2 X 35.5)
Moles of CaCl2 = 11.1/111= 0.1 mol
c = 0.1/0.1 = 1M (Volume of solution = 100ml = 0.1L)

Now, CaCl2 dissociates in solution to form one mole of calcium cations and 2 moles of chloride anions
CaCl2 ⇔ Ca2+ + 2Cl-

So, concentration of chloride ion is twice that of CaCl2 and is 2M

Answer 2

Answer:

2M is the answer that is (option 2)