Question

11.1grams of calcium chloride is present in 100 ml of the aqueous solution. the chloride ion concentration is???nd pls solve this. ....​

Answer 1

Explanation:

since in ques we have 11.1 g cacl2 we will first calculate no of moles corresponding to 11.1 g ehich is equal to 0.1 mole as no of moles = given mass/ molar mass

and molar mass = 40+2*35.5 =111g

so no of moles = 11.1 / 111 = 0.1 mole

now as CaCl2 is in aq medium it will dissociate as

CaCl2 (aq) gives Ca2+(aq) + 2 Cl-(aq)

now since 1 mole is giving 2 mole cl- therefore 0.1 mole cacl2 will give 0.2 mole cl- ion . We can calculate concentration as Molarity = no of moles / vol of solution in L therefore conc of cl- ion will be 0.2 / 0.1 = 2M (as 100 ml = 0.1 L) (100 / 1000)

Answer 2

11.1g of CaCl2 is present in 100ml of aqueous solution . the chloride ion concentration is. 1. 1m 2.