Question

11/2√3-1 rationalise the denominator​

Answer 1

Answer:

the answer is5.5-1.4 = 4.1

Answer 2

$\huge\mathcal\red{Solution:-}$

$\frac{11}{2\sqrt{3} - 1} \\ \\ = \frac{11}{2\sqrt{3} - 1} × \frac{2\sqrt{3} + 1 } { 2\sqrt{3} + 1} \\ \\ \boxed{{a}^{2} - {b}^{2} = (a+b)(a-b)} \\ \\ = \frac{22\sqrt{3} +11}{ ({2\sqrt{3} })^{2} - 1 } \\ \\ \frac{11(2\sqrt{3} + 1) } { 12 - 1} \\ \\ = \frac{11(2\sqrt{3} + 1) } {11} \\ \\ = 2\sqrt{3} + 1$