Question

এস টি পি তে 11.2 লিটার এমোনিয়া তৈরি করার জন্য কি পরিমান অ্যামোনিয়াম ক্লোরাইড এর সাথে কলিচুন মিশিয়ে উত্তপ্ত করতে হবে​

Answer 1

Answer:

reactants: ammonium chloride and calcium hydroxide in the ratio of 2:3 by weight and must be heated about to 40 degree F ( 4.4 C )

Answer 2

The required answer is 8.5g.

S.T.P : Standard temperature and pressure(STP) refers to the nominal conditions in the atmosphere at sea level. These condition are 0 degrees  Celsius and 1 atmosphere (atm) of pressure. The STP value is important to physicists, chemists, and etc.

As per the question we need to find the how much ammoniam chloride mixed with calcium oxide.

The given data is

Volume of Ammonia is 11.2 liter in S.T.P.

Now

Molar Volume (Vₙ) = 22.4 liter/mol.

Therefore Number of mole(x)= V/V ₙ = $\frac{11.2}{22.4}$

                                                             = 0.5 moles

Molar mass of Ammonia (M) = 17g/mol

mass of 0.5 moles = n *M = 0.5*17g

                                           = 8.5g

Hence the required answer is 8.5g.

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