11.2 L of a gas at STP weight 14g. The gas can be (A) N2 (B) CO (C) B2H6 (D) N20
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2
Answer:
answer is B and C
Explanation:
Correct option is
B
CO
C
B
2
H
6
No. Of moles of that gas=
22.4 L
11.2 L
=
2
1
mole
Given mass =14g
We know,
No. Of moles =given mass /molecular mass
2
1
mole=
molar mass
14
molar mass=28g
the molar mass of CO is 28
also, the molar mass of B
2
H
6
is 28g
Thus, the gas could be CO or B
2
H
6
Hence, the correct options are B and C
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